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18 mag 2015 · Using the C# language constructs, you cannot explicitly call the base function from outside the scope of A or B.If you really need to do that, then there is a flaw in your design - i.e. that function shouldn't be virtual to begin with, or part of the base function should be extracted to a separate non-virtual function.
6 ott 2022 · Remarks. The warning shows up on the first virtual function definition of a type (it can be a virtual destructor if it isn't public), once per type. Since a definition can be placed separately from a declaration, it may not always have any of the virtual specifiers. But the warning is still valid: it checks the actual 'virtuality' of a function.
30 giu 2015 · A pure virtual function is a function that must be overridden in a derived class and need not be defined. A virtual function is declared to be “pure” using the curious =0 syntax. For example: class Base {. public: void f1(); // not virtual. virtual void f2(); // virtual, not pure.
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The spec draft (n3242) says. If a virtual function is marked with the virt-specifier override and does not override a member function of a base class, the program is ill-formed.
19 feb 2015 · B* pb = &c; pb->foo(); // uses the virtual function. pb->B::foo(); // but you can force to use the function, ignoring the virtuality. Possible approach using a virtual and a non virtual function. With little additional cost you could emulate this behaviour in your code, using a comibnation of 2 functions: a private virtual one, and a public non ...
A class designed to be used polymorphically at run-time (through a pointer to the base class) should declare the destructor virtual. This allows the derived parts of the object to be properly destroyed, even when the object is destroyed through a pointer to the base class. virtual ~Base() = default; // data members etc.
